What is the formula for tin(II) fluoride?

The formula for tin(II) fluoride is SnF2 because it represents the correct stoichiometry based on the oxidation state of tin in this compound. The (II) in tin(II) indicates that tin has a +2 oxidation state. Fluorine, being a halogen, typically has an oxidation state of -1.

To balance the charge in the compound, two fluoride ions (each with a -1 charge) are required to pair with one tin ion with a +2 charge. Therefore, one tin(II) ion combines with two fluoride ions, resulting in the formula SnF2. This reflects the necessary balance of positive and negative charges in a neutral compound.

Other options do not represent the correct stoichiometry for tin(II) fluoride, as they either have the wrong number of fluoride ions or do not match the oxidation state of tin accurately.